20 August, 2010
miles biked-14
water used - 7.3875 gallons (7.6125 surplus)
While I got some initial calculations from Jamie Borell at Innovative Power Systems, I needed some specific information about my hypothetical PV solar array to maximize my electricity budget. While most solar arrays are sized to the need of the particular house, my solar system was sized in the opposite way-maximizing the amount of sun energy I can capture to determine what my electricity budget will be.
Here is how it was calculated:
There are 3 main factors to consider when sizing a solar array:
1_The square footage of your house
2_Options for solar panel orientation
(A) Solar panels can be angled at 45 degrees (for a MN climate) in which case they are maximized for the most energy captured per panel. however, with this system there must be room left for shadows which will fall on panels located behind. This reduces the sq footage of the roof available for sun capture by a factor of 2.5. (The square footage of your house divided by 2.5)
(B) Solar panels can be placed flat on the roof. This way, you are able to use the most roof area for solar energy capture, however, the angle is not ideal and the efficiency of the panels is reduced by 20%.
3_There are different "efficiencies" for solar panels, outputs range from 8watts/sq ft to 20w/sq ft (and probably more options exist). Generally the most expensive the panel, the greater energy output in watts/sq ft you can achieve.
To calculate the amount of solar power you can capture on your own roof:
1_Find the square footage of your house (mine is 1790 sf)
2_Decide if you would like to go with 45 degree panels (cheaper) or flat panels (more panels required=more expensive)
Divide the square footage of your house by 2.5 for 45 degree angle panels (this is your available sq footage)
3_Determine the watt/sq ft output of your panels (this information is found on manufacturer's websites) (I'm going with 8w/sq ft)
4_Calculate:
(Available square footage of your house for solar) x (Efficiency of panels in watts/sq ft) = Size of your system in watts
(Size of your system in watts) x Either (1.28 kWh/watt installed for 45 degree panels) or (1.043kWh/watt installed for flat panels)
=kWh/yr
Divide by 365 for kWh/day
Being that my goal is to maximize my solar power (regardless of cost) I am going with the flat solar panel arrangement. This system would be more expensive (because there are more solar panels involved, but would result in a higher energy output, see calculations below):
45 degree angle option(1790 sq ft/2.5) reduction in sq footage due to shadows:
1790 sq ft/2.5=716 sq ft x8w/sf =5728 w system (5.7kw system)
(5.7 kw) x1.28 kWh/watt installed =7331 kWh/yr =20.08 kWh/day
(3.35 kWh/person/day)
vs.
Flat solar panels option covering all 1790 sq ft:
1790 sq ft x 8w/sf =14,320 watt system (14.3 kw system)
(14.3kw) x1.043 kWh/watt installed = 14,935 kWh/yr (14.9 kWh/yr) =40.9 kWh/day
(6.82 kWh/person/day)
so my electricity budget per day is 6.82 kWh.
(Thanks to Pat Smith at CSBR! (numbers from previous Weidt Group calculations))
Other noteworthy things happening today was it was the first time I've eaten at a restaurant since the project began. Common Roots
http://www.commonrootscafe.com/ is only a block south of me and an excellent source of local foods. As much as possible, their food and drinks are local. While I have to ask about specific meals because the sourcing changes constantly, they are a great local restaurant option (they are gonna get really sick of me by the end of this project). I had radish cakes / seared and topped with sunflower sprouts and toasted hazelnuts and a local Brau Bros (Lucan, MN) sheephead ale :) I also got some great advice from friends about local food options and extras from gardens. Thanks Dan, Nate, Sarah and Katy! Get me that garlic Dale :)